Answer:
C
Explanation:
Using only renewable energy is a way that you can benefit the Earth. For example, if we switch to solar energy, then we would be more sustained because you can use solar energy more than once. Renewable resources are produced in a short time or a lot is available. So, the answer is C.
A student is comparing the speed of sound in air and water. She measures the frequency, f, and wavelength, λ, of sound waves in both air and water. The results are shown in the following table. Based on her data, how does the speed of sound in water compare to the speed of sound in air?
A.The speed of sound through water is 4.3 times faster than sound through air.
B.The speed of sound through water is 2.6 times slower than sound through air.
C.The speed of sound through water is 8.4 times faster than sound through air.
D.The speed of sound through air is approximately equal to the speed of sound through water.
Answer:
Option A. The speed of sound through water is 4.3 times faster than sound through air.
Explanation:
To answer the question correctly, we shall determine the speed of the wave in both cases. This is illustrated below:
For Air:
Frequency (fₐ) = 195 Hz
Wavelength (λₐ) = 1.76 m
Velocity (vₐ) =?
vₐ = λₐfₐ
vₐ = 1.76 × 195
vₐ = 343.2 m/s
For Water:
Frequency (fᵥᵥ) = 195 Hz
Wavelength (λᵥᵥ) = 7.6 m
Velocity (vᵥᵥ) =?
vᵥᵥ = λᵥᵥfᵥᵥ
vᵥᵥ = 7.6 × 195
vᵥᵥ = 1482 m/s
Finally, we shall compare the speed in water to that of air. This can be obtained as follow:
Velocity in air (vₐ) = 343.2 m/s
Velocity in water (vᵥᵥ) = 1482 m/s
Water : Air
vᵥᵥ : vₐ =>
vᵥᵥ / vₐ = 1482 / 343.2
vᵥᵥ / vₐ = 4.3
Cross multiply
vᵥᵥ = 4.3 × vₐ
Thus, the speed in water is 4.3 times the speed in air.
Option A gives the correct answer to the question.
pair of two hollow cups is term as
Answer:
Magdeburg hemispheres are a pair of large copper hemispheres, with mating rims.
Explanation:
They were used to demonstrate the power of atmospheric pressure. When the rims were sealed with grease and the air was pumped out, the sphere contained a vacuum and could not be pulled apart by teams of horses.
You need to produce a set of cylindrical copper wire 3.5 m long that will have a
resistance of 0.125 Ω each. What will be the mass of each of these wires?
(ρ = 1.72X10-8 Ωm, density of copper = 8.9X103 kg/m3)
Solution :
We know, resistance is given by :
[tex]R = \dfrac{\rho l}{A}[/tex]
[tex]A = \dfrac{\rho l }{R}\\\\A = \dfrac{1.72\times 10^{-8} \times 3.5 }{0.125}\\\\A = 4.816 \times 10^{-7} \ m^2[/tex]
Now, we know mass of wire is given by :
[tex]Mass = Density \times Volume\\\\\M = 8.9 \times 10^3 \times 4.816 \times 10^{-7} \times 3.5 kg\\\\M = 0.01500\ kg\\\\M = 15.00\ gram[/tex]
Hence, this is the required solution.
Given:
Length of wire, l = 3.5 mResistance, R = 0.125 ΩThe resistance will be:
→ [tex]R = \frac{\rho l}{A}[/tex]
or,
→ [tex]A = \frac{\rho l}{R}[/tex]
By substituting the values, we get
[tex]= \frac{1.72\times 10^{-8}\times 3.5}{0.125}[/tex]
[tex]= 4.816\times 10^{-7} \ m^2[/tex]
hence,
The mass will be:
→ [tex]Mass = Density\times Volume[/tex]
[tex]= 8.9\times 10^3\times 4.816\times 10^{-7}\times 3.5[/tex]
[tex]= 0.01500 \ kg[/tex]
[tex]= 15.00 \ g[/tex]
Thus the above answer is right.
Learn more about mass here:
https://brainly.com/question/17108656
Appliances A, B, and C consume 250, 480 and 1450 watts of power, respectively. The system voltage is 120V, and the circuit breaker is rated at 15 amps. Which combinations of the three appliances can be on at the same time, and which combinations will trip the circuit breaker
Answer:
Appliance A and B can work together without tripping
Explanation:
We will calculate the amount of current consumed by each appliances.
Appliance A
P = VI
I = P/V
I = 250/120 = 2.08 A
Appliance B
I = 480 /120 = 4 A
Appliance C
I = 1450/120
I = 12.08 A
Hence, appliance C will trip the circuit as it consumes a lot of electricity.
If, for a given velocity, the maximum range is at a projection angle of 45, then there must be equal ranges for angles above and below this. Show this explicitly.
Explanation:
The range R of a projectile is given by
[tex]R = \frac{v_0^2}{g} \sin 2\theta[/tex]
The maximum range [tex]R_{max}[/tex] occurs when [tex]\sin 2\theta = 1\:\text{or}\:\theta = 45°[/tex]. Let [tex]\alpha[/tex] be the angle above or below 45°. Now let's look at the ranges brought about by these angle differences.
Case 1: Angle above 45°
We can write the range as
[tex]R_+ = \dfrac{v_0^2}{g} \sin 2(45° + \alpha)= \dfrac{v_0^2}{g} \sin (90° + 2\alpha)[/tex]
[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} (\sin 90° \cos 2\alpha + \cos 90° \sin 2\alpha)[/tex]
[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} \cos 2\alpha\:\:\:\:\:(1)[/tex]
Case 2: Angle below 45°
We can write the range as
[tex]R_- = \dfrac{v_0^2}{g} \sin 2(45° - \alpha)= \dfrac{v_0^2}{g} \sin (90° - 2\alpha)[/tex]
[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} (\sin 90° \cos 2\alpha - \cos 90° \sin 2\alpha)[/tex]
[tex]\:\:\:\:\:\:\:= \dfrac{v_0^2}{g} \cos 2\alpha\:\:\:\:\:(2)[/tex]
Note that the equations (1) and (2) are identical. Therefore, the ranges are equal if they differ from 45° by the same amount.
What does the law of the conservation of energy state?
A 45.00 kg person in a 43.00 kg cart is coasting with a speed of 19 m/s before it goes up a hill.Assuming there is no friction, what is the maximum vertical height the person in the cart can reach?
Answer:
the maximum vertical height the person in the cart can reach is 18.42 m
Explanation:
Given;
mass of the person, m₁ = 45 kg
mass of the cart, m₂ = 43 kg
velocity of the system, v = 19 m/s
let the maximum vertical height reached = h
Apply the principle of conservation mechanical energy;
[tex]P.E = K.E\\\\mgh_{max} = \frac{1}{2} mv^2_{max}\\\\gh_{max} = \frac{1}{2} v^2_{max}\\\\h_{max} = \frac{v_{max}^2}{2g} \\\\h_{max} = \frac{19^2}{2\times 9.8} \\\\h_{max} = 18.42 \ m[/tex]
Therefore, the maximum vertical height the person in the cart can reach is 18.42 m
A gymnast is swinging on a high bar. The distance between his waist and the bar is 1.06 m, as the drawing shows. At the top of the swing his speed is momentarily zero. Ignoring friction and treating the gymnast as if all of his mass is located at his waist, find his speed at the bottom of the swing.
Answer: The speed of gymnast at the bottom of the swing is 6.44 m/s.
Explanation:
Given: Distance = 1.06 m
According to the law of conservation of energy, the speed is calculated as follows.
[tex]mgh = - mgh + \frac{1}{2}mv^{2}\\gh = - gh + \frac{1}{2}v^{2}\\v = \sqrt{4gh}[/tex]
where,
g = acceleration due to gravity = 9.8 [tex]m/s^{2}[/tex]
h = distance
v = speed
Substitute the values into above formula as follows.
[tex]v = \sqrt{4gh}\\= \sqrt{4 \times 9.8 m/s^{2} \times 1.06}\\= 6.44 m/s[/tex]
Thus, we can conclude that speed of gymnast at the bottom of the swing is 6.44 m/s.
a ball dropped from a height of 10 meters will bounce more times before coming to rest than a ball dropped from a height of 5 meters. Use evidence and scientific reasoning to explain this phenomenon.
Answer:
plz mark brainliest again lol :)
Explanation:
When you drop a ball from a greater height, it has more kinetic energy just before it hits the floor and stores more energy during the bounce—it dents farther as it comes to a stop.
Answer:
When you drop a ball from a greater height, there is more potential energy. When you release the ball, the potential energy turns into kinetic energy. When the ball bounces off the ground, the ball go upward and then it has more potential energy. Then when it goes down it has more kinetic energy. The ball keeps doing this until there is not enough potential energy left.
Explanation:
A family uses an electric frying pan with a power rating of 1.2 X 10^3 W. Although the pan is thermostatically controlled, its element was drawing power for 6.3 X 10^2 min in a period of one month. Calculate the electrical energy in kWh used by the pan during the month
Answer:
378 KWh
Explanation:
We'll begin by converting 1.2×10³ W to KW. This can be obtained as follow:
10³ W = 1 KW
Therefore,
1.2×10³ W = 1.2×10³ W × 1 KW / 10³ W
1.2×10³ W = 1.2 KW
Next, we shall convert 6.3×10² mins to hours (h). This can be obtained as follow:
60 mins = 1 h
Therefore,
6.3×10² mins = 6.3×10² mins × 1 h / 60 mins
6.3×10² mins = 10.5 h
Finally, we shall determine the electrical energy in KWh used for 1 month (i.e 30 days). This can be obtained as follow:
Power (P) = 1.2 KW
Time (t) for 1 month (30 days) = 10.5 h × 30
= 315 h
Energy (E) =?
E = Pt
E = 1.2 × 315
E = 378 KWh
Thus, the electrical energy used for 1 month (i.e 30 days) is 378 KWh.
What is the average speed (in km/h) of Zhana, who runs to the store that is 4.0 km away in 30.0 minutes?
0.13 km/ h
8.0 km/h
2.0 km/h
Answer:
2.0km/h.
Explanation:
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Which scenario is an example of a scientific way of thinking?
O A. A scientist collects different kinds of rocks and then takes them to
museums where the public can appreciate them.
B. A scientist makes a judgment that a rock sample is volcanic
because of the rock's texture and mineral composition.
O C. A scientist decides that taking rocks from national parks is wrong
because later park visitors will not be able to see them.
D. A scientist makes a judgment that rocks are more interesting to
study than living organisms because they tell more about Earth's
history
The scenario when a scientist makes a judgment that a rock sample is volcanic because of the rock's texture and mineral composition is an example of a scientific way of thinking, therefore the correct answer is option B.
What is the scientific claim?Scientific claims are statements made in science based on an experiment.
These Scientific claims are backed by experimental data and their true results obtained from scientific investigation and experimentation.
A good illustration of a scientific mode of thinking is when a scientist determines that a rock sample is volcanic based on its texture and mineral makeup.
Thus, The scenario when a scientist makes a judgment that a rock sample is volcanic because of the rock's texture and mineral composition is an example of a scientific way of thinking, therefore the correct answer is option B.
To learn more about the scientific claims here, refer to the link
brainly.com/question/11088441
#SPJ2
a 2kg block of wood starts at rest and slides down a ramp. Its initail height is 12m. if the final velocity of the block is 13m/s, determine the energy of this system that has been turned into heat
Answer:
E = 66.44 J
Explanation:
From the law of conservation of energy:
Total Mechanical Energy at Start = Total Mechanical Energy at the End
Potential Energy at Start = Kinetic Energy at End + Energy Lost
[tex]mgh = \frac{1}{2} mv^2 + E\\\\E = mgh - \frac{1}{2} mv^2\\\\[/tex]
where,
E = Energy turned into heat = ?
m = mass of block = 2 kg
g = acceleration due to gravity = 9.81 m/s²
h = height = 12 m
v = final speed = 13 m/s
Therefore,
[tex]E = (2\ kg)(9.81\ m/s^2)(12\ m)-\frac{1}{2} (2\ kg)(13\ m/s)^2\\\\E = 235.44\ J - 169\ J\\[/tex]
E = 66.44 J
Model a hydrogen atom as a three-dimensional potential well with Uo = 0 in the region 0 < x
a. 283 eV
b. 339 eV
c. 113 eV
d. 226 eV
This question is incomplete, the complete question is;
Model a hydrogen atom as a three-dimensional potential well with U₀ = 0 in the region 0 < x < L, 0 < y < L and 0 < z < L, and infinite otherwise, with L = 1.0 × 10⁻¹⁰ m.
Which of the following is NOT one of the lowest three energy levels of an electron in this model?
a. 283 eV
b. 339 eV
c. 113 eV
d. 226 eV
Answer:
the lowest three energy are; 113 eV, 225 eV, and 339 eV.
Hence Option a) 283 eV is not among the three lowest energy
Explanation:
Given the data in the question;
Three dimension cube or particle in a cubic box
the energy value is given by;
[tex]E_{nx,ny,nz[/tex] = [tex]( n_x^2 + n_y^2 + n_z^2 )[/tex] × π²h"² / 2ml²
where h" = h/2π and h is Planck's constant ( 6.626 × 10⁻³⁴ m² kg / s )
m is mass of electron ( 9.1 × 10⁻³¹ kg )
l is length of side of box ( 1.0 × 10⁻¹⁰ m )
for ground level ( [tex]n_x = n_y = n_z = 1[/tex] )
so
[tex]( n_x^2 + n_y^2 + n_z^2 )[/tex] × π²h"² / 2ml²
since h" = h/2π
[tex]( n_x^2 + n_y^2 + n_z^2 )[/tex] × π²h² / (2π)²2ml²
so we substitute
[tex]E_{111[/tex] = ( 1² + 1² + 1² ) × [ π²( 6.626 × 10⁻³⁴ )² ] / [ (2π)² × 2 × 9.1 × 10⁻³¹ kg × ( 1.0 × 10⁻¹⁰)² ]
[tex]E_{111[/tex] = 3 × [ (4.333188779 × 10⁻⁶⁶) / ( 7.185072 × 10⁻⁴⁹ ) ]
[tex]E_{111[/tex] = 3 × [ 6.03082165 × 10⁻¹⁸ ]
Now, we know that electric charge = 1.602 x 10⁻¹⁹
so
[tex]E_{111[/tex] = 3 × [ (6.03082165 × 10⁻¹⁸) / (1.602 x 10⁻¹⁹) ]
[tex]E_{111[/tex] = 3 × [ 37.645578 ]
[tex]E_{111[/tex] = 112.9 ≈ 113 eV
[tex]E_{211[/tex] = [tex]( n_x^2 + n_y^2 + n_z^2 )[/tex] × π²h² / (2π)²2ml²
we substitute
[tex]E_{211[/tex] = ( 1² + 1² + 2² ) × [ 37.645578 ]
[tex]E_{211[/tex] = 6 × [ 37.645578 ]
[tex]E_{211[/tex] = 225.87 ≈ 226 eV
[tex]E_{221[/tex] = [tex]( n_x^2 + n_y^2 + n_z^2 )[/tex] × π²h² / (2π)²2ml²
we substitute
[tex]E_{221[/tex] = ( 2² + 2² + 1² ) × [ 37.645578 ]
[tex]E_{211[/tex] = 9 × [ 37.645578 ]
[tex]E_{211[/tex] = 338.8 ≈ 339 eV
Therefore, the lowest three energy are; 113 eV, 225 eV, and 339 eV.
Hence Option a) 283 eV is not among the three lowest energy
Genes are arranged on a twisted strands called.
Si un electrón recorre el acelerador lineal de Stanford de 2 millas de longitud a 99% de la velocidad de la luz, ¿Cuál es la longitud del acelerador según el electrón?
Assume the following vehicle are all moving at the same speed.it would be harder to change the velocity of which vehicle.a.bicycle.B.car.c.motorcycle.D.semi-tractor trailer.
Answer:im just guessing d but i think its d though
Explanation:
it pretty obvious
amount of pressure of liquid increases with ?
Answer: Pressure increases as the depth increases.
Answer:
depths cause it help it with a lot and that it the answer
As a 2.0-kg object moves from (4.4 i + 5j) m to ( 11.6 i - 2j) m, the constant resultant force
acting on it is equal to (41 - 9j) N. If the speed of the object at the initial position is 4.0 m/s,
what is its kinetic energy at its final position?
Answer:
Answer:
v_f = 10.38 m / s
Explanation:
For this exercise we can use the relationship between work and kinetic energy
W = ΔK
note that the two quantities are scalars
Work is defined by the relation
W = F. Δx
the bold are vectors. The displacement is
Δx = r_f -r₀
Δx = (11.6 i - 2j) - (4.4 i + 5j)
Δx = (7.2 i - 7 j) m
W = (4 i - 9j). (7.2 i - 7 j)
remember that the dot product
i.i = j.j = 1
i.j = 0
W = 4 7.2 + 9 7
W = 91.8 J
the initial kinetic energy is
Ko = ½ m vo²
Ko = ½ 2.0 4.0²
Ko = 16 J
we substitute in the initial equation
W = K_f - K₀
K_f = W + K₀
½ m v_f² = W + K₀
v_f² = 2 / m (W + K₀)
v_f² = 2/2 (91.8 + 16)
v_f = √107.8
v_f = 10.38 m / s
what is parallelogram law of vector addition ???
Answer:
According to the parallelogram law of vector addition if two vectors act along two adjacent sides of a parallelogram(having magnitude equal to the length of the sides) both pointing away from the common vertex, then the resultant is represented by the diagonal of the parallelogram passing through the same common vertex
Explanation:
DL: Activity 2.3 Resistance Complete the questions based on the Resistance presentation. a. All resistors ___________ or _____________ the flow of electrons. b. As resistance __________________ current _______________________
DL: Activity 2.3 Resistance
Complete the questions based on the Resistance presentation.
a. All resistors ___________ or _____________ the flow of electrons.
b. As resistance __________________ current _______________________
Answer:a) limits or opposes
b) increases, decreases
Explanation:Resistors are electrical devices used to resist, limit, oppose or hinder the flow of electrons in a circuit. This resistance causes a reduction in current and an increase in voltage in the circuit. In order words, as resistance increases, the current decreases and voltage increases.
This was further stated by Ohm's law that states that as long as the resistance in a wire/conductor remains constant, the voltage across it is directly proportional to the current flowing through a conductor. i.e
V = IR
Where;
R = constant called resistance
I = current flowing through the wire
V = voltage across the wire
g A 50 kg box is resting on a horizontal surface. Results for item 1. 1 1 / 1 point Determine the weight of the box in [N]. Correct answer: 490 Results for item 2. 2 1 / 1 point Determine the magnitude of the normal force acting on the box in [N]. Correct answer: 490 Results for item 3. 3 0 / 1 point Find the magnitude of the upward applied force, in [N], necessary to lift the box with an acceleration of 1 m/s2
Answer:
(a) 490 N
(b) 490 N
(c) 540 N
Explanation:
mass, m = 50 kg
acceleration, a = 1 m/s2
(a) The weight is given by
W = m g = 50 x 9.8 = 490 N
(b) The normal force is
N = m g = 490 N
(c) Let the force required is F.
Use Newton's second law
F - m g = m a
F = m(g + a)
F = 50(9.8 + 1)
F = 540 N
A steel playground slide is 5.25 m long and is raised 2.75 m on one end. A 45.0 kg child slides down from the top starting at rest. The final speed of the child at the bottom is 6.81 m/s. Find the average force of friction between the child and the slide.
Answer:
[tex]F=32.24N[/tex]
Explanation:
From the question we are told that:
Height [tex]h= 2.75 m[/tex]
Length[tex]l = 5.25 m[/tex]
Mass [tex]m=45kg[/tex]
Final speed [tex]v_f=6.81[/tex]
Generally the equation for Potential Energy P.E is mathematically given by
[tex]P.E=mgh[/tex]
Therefore
Initial potential energy
[tex]P.E_1=45*9.8*2.75 \\\\P.E_1= 1212.75 J[/tex]
Generally the equation for Kinetic Energy K.E is mathematically given by
[tex]K.E=0.5mv^2[/tex]
Therefore
Final kinetic energy
[tex]K.E_2= 1/2*45*6.81*6.81 \\\\K.E_2= 1043.46J[/tex]
Generally the equation for Work_done is mathematically given by
[tex]W=P.E_1-K.E_2\\\\W=169.3[/tex]
Therefore
[tex]F=\frac{W}{d}\\\\F=\frac{169.3}{5.25}[/tex]
[tex]F=32.24N[/tex]
A banked curve is designed for a roadway. The curve is designed so that a car traveling at 19.2 m/s can negotiate it without relying on the force of static friction. The radius of the curve is 51.2 in and the car has a mass of 2300 kg. a. What angle is the curve banked at (degrees)? b. What is the magnitude of the Normal force (N) between the road and the car when it is traveling at the designed speed? c. If a careless driver tries to negotiate the curve at a speed of 25 m/s ,will the direction of the frictional force be inward or outward?
Consider the cylindrical weir of diameter 3 m and length 6m. If the fluid on the left has a specific gravity of 0.8, find the magnitude and direction of the resultant force
This question is incomplete, the complete question is;
Consider the cylindrical weir of diameter 3m and length 6m. If the fluid on the left has a specific gravity of 1.6 and on the right has a specific gravity of 0.8, Find the magnitude and direction of the resultant force.
Answer:
- the magnitude of the resultant force is 557.32 kN
- the direction of resultant force is 48.29°
Explanation:
Given the data in the question and the diagram below,
First we work on the force on the left hand side.
Left Horizontal
[tex]F_{LH[/tex] = βgAr
here, h = 3/2 = 1.5 m, β = 1.6, g = 9.81 m/s², A = 3 m × 6 m = 18 m²
we substitute
[tex]F_{LH[/tex] = βgAh = ( 1.6 × 1000 ) × 9.81 × 18 × 1.5 = 423792 N
Left Vertical
[tex]F_{LV[/tex] = ( βgπh² / 2 ) × W
we substitute
[tex]F_{LV[/tex] = [ ( ( 1.6 × 1000 ) × 9.81 × π(1.5)² ) / 2 ] × 6 = 332845.458 N
Now we go to the right hand side
Right Horizontal
[tex]F_{RH[/tex] = βgAh
here, h' = 1.5/2 = 0.75 m, β = 0.8, g = 9.81 m/s², A = 1.5 m × 6 m = 9 m²
we substitute
[tex]F_{RH[/tex] = ( 0.8 × 1000 ) × 9.81 × 9 × 0.75 ) = 52974 N
Right Vertical
[tex]F_{RV[/tex] = ( βgπh² / 4 ) × W
we substitute
[tex]F_{RV[/tex] = [ ( ( 0.8 × 1000 ) × 9.81 × π(1.5)² ) / 4 ] × 6 = 83211.36 N
Hence
Fx = [tex]F_{LH[/tex] - [tex]F_{RH[/tex] = 52974 N - 423792 N = 370818 N
Fy = [tex]F_{LV[/tex] + [tex]F_{RV[/tex] = 332845.458 N + 83211.36 N = 416056.818 N
R = √( Fx² + Fy² ) = √[ (370818 N)² + (416056.818 N)² ] = 557323.3 N
R = 557.32 kN
Therefore, the magnitude of the resultant force is 557.32 kN
Direction of resultant force;
tanθ = Fy / Fx
we substitute
tanθ = 416056.818 N / 370818 N
tanθ = 1.121997
θ = tan⁻¹( 1.121997 )
θ = 48.29°
Therefore, the direction of resultant force is 48.29°
What can/should we be doing now to prepare for the mass migration to come?
Answer:
Here are a few recommendations based on IOM's Migration Governance Framework: Countries should promote stability, education and employment opportunities and reduce the drivers of forced migration, including by promoting resilience, thereby enabling individuals to make the choice between staying or migrating.
Explanation:
thank me later
A flashlight converts?
1. Electrical energy into electromagnetic energy.
2. Kinetic energy into potential energy
3. Thermal energy into electromagnetic energy.
4. Chemical energy to radiant energy
Answer:
Energy conversion in flashlight.
Explanation:
When the switch of a flashlight is on, then the batteries inside them will be connected in a circuit and chemical energy from the batteries will be converted into electrical energy and then the electrical energy will be converted into light energy.
Light energy is also called electromagnetic energy.
Hence, among the given options the correct one is the first option that is:
1. Electrical energy into electromagnetic energy is the answer.
A singly charged ion (q=−1.6×10−19) makes 7.0 rev in a 45 mT magnetic field in 1.29 ms. The mass of the ion in kg is
Answer:
[tex]m=1.47\times 10^{-24}\ Kg[/tex]
Explanation:
Given that,
Charge, [tex]q=1.6\times 10^{-19}\ C[/tex]
Revolution = 7 rev
magnetic field, B = 45 mT
Time, t = 1.29 ms
We need to find the mass of the ion. Let m be the mass. The formula for the mass in terms of time period is given by :
[tex]m=\dfrac{qBT}{2\pi}\\\\m=\dfrac{1.6\times 10^{-19}\times 45\times 10^{-3}\times 1.29\times 10^{-3}}{2\pi}\\\\m=1.47\times 10^{-24}\ Kg[/tex]
So, the mass of the ion is equal to [tex]1.47\times 10^{-24}\ Kg[/tex].
18 of 25
The practice of science can answer only scientific questions. And scientific
questions guide the design of investigations. What must be true of the
possible answers to a scientific question?
A. They agree with all prior experiments,
B. They can be supported by evidence,
C. They are popular with a majority of scientists,
D. They lead to increased funding of scientific research,
Answer:
B
Explanation:
Cause its true
A point source of light illuminates an aperture 1.70 m away. A 11.0 cm -wide bright patch of light appears on a screen 0.800 m behind the aperture. Part A How wide is the aperture
Answer:
7.48 cm
Explanation:
The diagrammatic representation of information is shown in the image below:
From the image, Δ X₁X₂ and Δ Y₁Y₂ are equivalent triangles.
where;
X₁X₂ = width of the aperture
Using equivalent triangles, It implies that:
[tex]\implies \dfrac{X_1X_2}{Y_1Y_2} = \dfrac{1.70}{1.70+0.800} \\ \\ \implies X_1X_2=\dfrac{1.70}{1.70+0.800}\times 11.0[/tex]
[tex]X_1X_2= \dfrac{1.70}{2.50}\times 11.0 cm[/tex]
X₁X₂ = 7.48 cm